(4x^4+4x^3-5)-(4x^2-3x+7)=

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Solution for (4x^4+4x^3-5)-(4x^2-3x+7)= equation:


Simplifying
(4x4 + 4x3 + -5) + -1(4x2 + -3x + 7) = 0

Reorder the terms:
(-5 + 4x3 + 4x4) + -1(4x2 + -3x + 7) = 0

Remove parenthesis around (-5 + 4x3 + 4x4)
-5 + 4x3 + 4x4 + -1(4x2 + -3x + 7) = 0

Reorder the terms:
-5 + 4x3 + 4x4 + -1(7 + -3x + 4x2) = 0
-5 + 4x3 + 4x4 + (7 * -1 + -3x * -1 + 4x2 * -1) = 0
-5 + 4x3 + 4x4 + (-7 + 3x + -4x2) = 0

Reorder the terms:
-5 + -7 + 3x + -4x2 + 4x3 + 4x4 = 0

Combine like terms: -5 + -7 = -12
-12 + 3x + -4x2 + 4x3 + 4x4 = 0

Solving
-12 + 3x + -4x2 + 4x3 + 4x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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